Assignment #92 Heron's Formula

Code

    /// Name: DeeJay Cerezo
/// Period: 7
/// Program Name: Heron
/// File Name: Heron.java
/// Date Finished: 3/4/2016
 public class Heron
{
	public static void main( String[] args )
	{
		double a;
		
		a = triangleArea(3, 3, 3);
		System.out.println("A triangle with sides 3,3,3 has an area of " + a );

		a = triangleArea(3, 4, 5);
		System.out.println("A triangle with sides 3,4,5 has an area of " + a );
 
		a = triangleArea(7, 8, 9);
		System.out.println("A triangle with sides 7,8,9 has an area of " + a );

		System.out.println("A triangle with sides 5,12,13 has an area of " + triangleArea(5, 12, 13) );
		System.out.println("A triangle with sides 10,9,11 has an area of " + triangleArea(10, 9, 11) );
		System.out.println("A triangle with sides 8,15,17 has an area of " + triangleArea(8, 15, 17) );
        System.out.println("A triangle with sides 9, 9, 9 has an area of " + triangleArea(9, 9, 9)   );
        //Using a method is easier to find another triangle's area
	}
 
	public static double triangleArea( int a, int b, int c )
	{
		// it computes the area of a triangle whose sides have lengths a, b, and c
        
		double s, A;

		s = (a+b+c) / 2.0;
		A = Math.sqrt( s*(s-a)*(s-b)*(s-c) );

		return A;
		// ^ after computing the area, "return" it
        //HeronsFormula = 30 lines of code
        //HeronsFormulaNoMethod = 49 lines of code
        //Both methods produce the same output
        //Fixing the bug of dividing the triangle by two is easier because only one line has to be fixed compared to 5
	}
}

    
    
Picture of the output

    
    Assignment